If it's not what You are looking for type in the equation solver your own equation and let us solve it.
15x^2+10x-68=0
a = 15; b = 10; c = -68;
Δ = b2-4ac
Δ = 102-4·15·(-68)
Δ = 4180
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4180}=\sqrt{4*1045}=\sqrt{4}*\sqrt{1045}=2\sqrt{1045}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{1045}}{2*15}=\frac{-10-2\sqrt{1045}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{1045}}{2*15}=\frac{-10+2\sqrt{1045}}{30} $
| 2/5(2x+5)+1/3(4x-1)=9 | | 15-x=2x+60 | | 3x=9÷3 | | 1+(2y-4)=-y(6) | | 2(5x+4)=69 | | 5b/3-6=4b | | (y-2)^2=9(-4÷3+2) | | 5*40=100x | | 36=8-2n | | 12/8=200x | | 26/5=100x | | 23=8p-12+5 | | 14y+2=50 | | 7-2n=8n-（-4年）= | | 8=-12r | | 1x/3+(X/3-1200)+3(X/3-1200)=x | | -24p+-24=24 | | 9=-7b/2+3 | | 90=3x-54 | | 8u+4=52 | | (x-8)+(x+2)=42 | | n(n-1)=66 | | 2(m+-4)=-6 | | 90=2x-54 | | 59x=17,33 | | 60x=17,33 | | 90=3x+54 | | 90=3x=54 | | 90=2x+54 | | 5(x-3)=2(2x-6) | | 5（x-3)=2(2x-6) | | A+x=(2A*x3) |